1. CH3CH2COCHCHCH2CN: Which orbitals overlap to form the sigma bond indicated? (

Question

1. CH3CH2COCHCHCH2CN: Which orbitals overlap to form the sigma bond indicated? (The arrow in the picture points to the triple bond between C & N)

A) sp2-sp2

B) sp-sp

C) sp3-sp3

2. What would be the major product of the following reaction? (3S)-3-methyl-1-pentene ---------> 1. BH3, THF/2. H2O2, OH-
A) (3S)-3-methyl-1-pentanol
B) (2S,3S)-3-methyl-2-pentanol + diastereomer
C)  Pentane where both a CH3 wedge and OH dashed line are on the 3rd carbon
(I'm just a beginner!! Sorry)

3. 2-butene -------> 1. Br2, non-nucleophilic solvent leads to
A) 2,3-dibromobutane where both the bromines have wedges

B) 2,3-dibromobutane where one bromine is wedged and one dashed + enantiomer

C) Both of these

Explanation / Answer

A) sp2-sp2

B) (2S,3S)-3-methyl-2-pentanol + diastereomer

B) 2,3-dibromobutane where one bromine is wedged and one dashed + enantiomer

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