C2H4Br2(aq) + 3 I- (aq) ---> C2H4(g) + 2Br- (aq) + I(subscript 3) ^- (aq) The ra

Question

C2H4Br2(aq) + 3 I- (aq) ---> C2H4(g) + 2Br- (aq) + I(subscript 3) ^- (aq)

The rate law is

rate = k [C2H4Br2] [ I^-]

where k=5.04x10^-3 M-1 s^-1

what are the missing entries?

Run        [C2H4Br2]0 (m)          [I-]0 (m)       initial rate of formation of c2h4

1                x                           0.164             0.000542

2                0.164                     y                   0.000271

3                0.164                     0.164             z

x=_______M

y=_______M

z=_______M

Explanation / Answer

Rate = k[C2H4Br2][I-]

k = 5.04x10^-3 M-1s^-1 = 0.00504

Run 1

[C2H4Br2]0 = x

[I-]0 = 0.164M

Rate = 0.000542

Rate = 0.00504*0.164*x = 0.000542

x = 0.656

Run 2

[C2H4Br2]0 = 0.164 M

[I-]0 = y

Rate = 0.000271

Rate = 0.00504*0.164*x = 0.000271

y = 0.328

Run 3

[C2H4Br2]0 = x0.164M

[I-]0 = 0.164M

Rate = z

k = 0.00504*0.164*0.164 = z

z= 0.656 = 0.0001355

x = 0.656 M

y = 0.328 M

z = 0.0001355 M/s

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