The masses of a potassium-40 atom, a proton, and a neutron are 39.963999 amu, 1.
ID: 816779 • Letter: T
Question
The masses of a potassium-40 atom, a proton, and a neutron are 39.963999 amu, 1.007825 amu, and 1.008665 amu, respectively. Calculate to four significant figures
a. the mass defect in amu, and
b. the energy released in MeV/nucleon, in the formation of from the appropriate number of protons and neutrons.
Explanation / Answer
mass defect=mass of P-40-total mass of proton-total mass of neutrons
mass defect=(39.96399)-(1007825x19)-(1.008665x21)
=0.3666 amu Ans
energy released=(mass defectx931 MeV)/mass of P-40
energy released=(0.3666 amux931 MeV)/39.963999 per nucleon
=8.538 MeV/nucleon Ans
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