In Question 4, what initial concentration of SCN should be entered into the ICE

Question

In Question 4, what initial concentration of SCN should be entered into the ICE table (in Mu moI/L)? Hint: Unit conversion: 1 mol/L = 10^6 pmol/L Question 4 Concepts: Read Introduction? in the supplementary material named Supplementary- Chem Equilibrium Method r, and answer Questions 4 and 5. The pdf file of the supplementary material should be on Canvas under Files. Question: For Trial 1 of an equilibrium reaction, 4 mL of 0.0007 mol/L Fe(N03)3 is combined with 1 mL of 0.0004 mol/L KSCN and 4 mL of 0.65 mol/L H NO3. The solvent for the metal and ligand solutions is 0.65 mol/L HNO3. What initial concentration of Fe3 should be entered into the ICE table (in Mu mol/L)? Hint: Unit conversion: 1 mol/L = 10^6 Mu mol/L

Explanation / Answer

Your question is a bit confusing but still I will try my best to answer it.

It is given that 4 mL of 0.0007 mol/L of Fe(NO3)3 is added

Fe(NO3)3 ------> Fe3+ + 3NO3-

So, initilal concentration of Fe3+ = initial concentration of Fe(NO3)3

                                                     = 0.0007 mol/L

                                                     = 0.0007 * 106 mol/L

                                                    = 700 mol/L

                   

It is given that 1 mL of 0.0004 mol/L of KSCN is added

KSCN ------> K+ + SCN-

So, initilal concentration of K+ = initial concentration of KSCN

                                                     = 0.0004 mol/L

                                                     = 0.0004 * 106 mol/L

                                                    = 400 mol/L

Hope it helps. Get back to me in case of any issues

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.