1) If the reaction NH 3 (aq)+ H 2 O(l) = NH 4 + (aq) + OH - (aq) has a reaction
ID: 815784 • Letter: 1
Question
1) If the reaction NH3(aq)+ H2O(l) = NH4+(aq) + OH-(aq) has a reaction equilibrium constant of 1.80x10-5, then what is the equilibrium constant be for NH4+ (aq) = NH3(aq) + H+(aq)? Show work. A) 1.8E-19 B) 5.6E-10 C) 1.8E-15 D) 5.6E-4
2) Phosphorus pentachloride gas decomposes to form phosphorus trichloride gas and chlorine gas. What is the equilibrium constant for this reaction if a reaction vessel has an initial concentration of phosphorus pentachloride of 1.60 M and the equilibrium concentration of 0.680 M?
1) If the reaction NH3(aq)+ H2O(l) = NH4+(aq) + OH-(aq) has a reaction equilibrium constant of 1.80x10-5, then what is the equilibrium constant be for NH4+ (aq) = NH3(aq) + H+(aq)? Show work. A) 1.8E-19 B) 5.6E-10 C) 1.8E-15 D) 5.6E-4
2) Phosphorus pentachloride gas decomposes to form phosphorus trichloride gas and chlorine gas. What is the equilibrium constant for this reaction if a reaction vessel has an initial concentration of phosphorus pentachloride of 1.60 M and the equilibrium concentration of 0.680 M?
Explanation / Answer
1)
NH3(aq)+ H2O(l) = NH4+(aq) + OH-(aq)
The equilibrium constant kb= 1.80 x 10^-5
NH4+ (aq) = NH3(aq) + H+(aq)
This reaction is the reverse of the first reaction.
So, equilibrium constant for reverse reaction is ka = Kw / Kb
ka = (1 x 10^-14) / (1.80x10-5) = 5.56 x 10^-10
Ka = 5.6 x 10^-10
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2)
PCl5(g) <---------------> PCl3(g) + Cl2(g)
I 1.60 0 0
C -x +x +x
E 1.60-x +x +x
But given equilibrium concentration of PCl5 = 0.680 = 1.60 - x
Thus, x = 1.60 - 0.680 = 0.920 M
[Cl2] = 0.920 M
[PCl3] = 0.920
[PCl5] = 0.680
Kc = [Cl2][PCl3] / [PCl5]
Kc = (0.920)^2 / 0.680
Kc = 1.24
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