****SUPER HARD MASTERING CHEM PROBLEM!!! PLEASE HELP!!! 1. Write an equation for

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Question

****SUPER HARD MASTERING CHEM PROBLEM!!! PLEASE HELP!!!

1. Write an equation for the formation of NO2(g) from its elements in its standard states.

Express your answer as a chemical equation. Identify all of the phases in your answer.

2. Find ?H?f for NO2(g) from Appendix IIB in the textbook.

Express your answer using one decimal place.

3.Write an equation for the formation of CaCO3(s) from its elements in its standard states. Write any reference to carbon as C(s).

Express your answer as a chemical equation. Identify all of the phases in your answer.

4.Find ?H?f for CaCO3(s) from Appendix IIB in the textbook.

Express your answer using one decimal place.

5.Write an equation for the formation of C2H4(g) from its elements in its standard states. Write any reference to carbon as C(s).

Express your answer as a chemical equation. Identify all of the phases in your answer.

6.Find ?H?f for C2H4(g) from Appendix IIB in the textbook.

Express your answer using one decimal place.

7. Write an equation for the formation of CH3OH(l) from its elements in its standard states. Write any reference to carbon as C(s).

Express your answer as a chemical equation. Identify all of the phases in your answer.

8. Find ?H?f for CH3OH(l) from Appendix IIB in the textbook.

Express your answer using one decimal place.

1. N2(g) + 2O2(g) --> 2NO2(g)

Dinitrogen and Dioxygen forms gaseous nitrite.

2. N2(g) + O2(g) <==> NO2(g)

deltaH reaction = deltaHf (NO2) - deltaHf (N2) - deltaHf (O2)

delta Hf for N2 = 0 kJ

delta Hf for O2 = 0 kJ

standard delta Hreaction of NO2 = 180.5 kJ

so using this

deltaH reaction = deltaHf (NO2) - deltaHf (N2) - deltaHf (O2)

180.5 = deltaHf (NO2) - 0

deltaHf (NO2) = 180.5 kJ

3. Ca(s) + C(g) + 3/2O2(g) -----> CaCO3(s)

4. deltaHreaction = deltaHf CaCO3(s) - deltaHf Ca(s) - deltaHf C(g) - 3/2 deltaHf O2(g)

so substituting the values given in the appendix deltaHf CaCO3 can be find out.

5. 2C(s) + 2H2(g) --> C2H4(g)

6. deltaHreaction = deltaHf C2H4(g) - 2deltaHf C(s) - 2deltaHf H2(g)

so substituting the values given in the appendix deltaHf C2H4 can be find out.

7. C(s) + 2H2(g) + 1/2O2 (g) -----> CH3OH(l)

8. deltaHreaction = deltaHf CH3OH(l) - deltaHf C(s) - 2deltaHf H2(g) - 1/2 deltaHf O2(g)

so substituting the values given in the appendix deltaHf CH3OH can be find out.

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