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An important reaction in the formation of photochemical smog is the reaction bet

ID: 814191 • Letter: A

Question

An important reaction in the formation of photochemical smog is the reaction between ozone and NO:

NO(g)+O3(g)--> NO2(g)+O2(g)

The reaction is first order in NO and O3. The rate constant of the reaction is 80 (1/M*s) at 25 C and 3.000 x 10^3 (1/M*s) at 75 C.

(a) If this reaction were to occur in single step, would the rate law be consistent with the observed order of the reaction for NO and O3? yes/no

(b) What is the value of the activation energy of the reaction?

(c) What is the rate of the reaction at 25 X when [NO]= 2.63 x 10^-6 M and [O3]=5.96 x 10^-9 M?

(d) Predict the values of the rate constant at the following temperatures:

10 C and 35 C

Explanation / Answer

For the given reaction,

(a) The rate law will be consistent even when the reaction occurs in a single step for the given reaction. The order with respect to both the reactants NO and O3 would remain first-order in all the cases.

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(b) Energy of activation (Ea)

using arrhenius relation,

ln(k2/k1) = Ea/R[1/T1 - 1/T2]

with,

k1 = 80 (1/M.s) at T1 = 25 + 273 = 298 K

k2 = 3 x 10^3 (1/M.s) at T2 = 75 + 273 = 348 K

R = gas constant

feeding the values,

ln(3 x 10^3/80) = Ea/8.314[1/298 - 1/348]

Ea = 62498 J/mol

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(c) Rate of reaction,

Rate = k[NO][O3]

with,

[NO] = 2.63 x 10^-6 M

[O3] = 5.96 x 10^-9 M

k = 80 (1/M.s)

we get,

Rate at 25 oC = 80 (2.63 x 10^-6) (5.96 x 10^-9)

                       = 1.254 x 10^-12 M/s

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(d) rate constant at,

T1 = 10 oC + 273 = 283 K

using arrhenius equation,

ln(k2/k1) = Ea/R[1/T1 - 1/T2]

with,

k1 = ? at 10 oC

k2 = 80 (1/M.s) at T1 = 25 + 273 = 298 K

Ea = 62498 J/mol

R = gas constant feeding the values,

feeding the values,

ln(80/k1) = 62498/8.314[1/283 - 1/298]

rate constant (k1) at 10 oC = 21.01 (1/M.s)

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rate constant at,

T1 = 35 oC + 273 = 308 K

using arrhenius equation,

ln(k2/k1) = Ea/R[1/T1 - 1/T2]

with,

k1 = ? at 35 oC

k2 = 3 x 10^3 (1/M.s) at T2 = 75 + 273 = 348 K

Ea = 62498 J/mol

R = gas constant feeding the values,

feeding the values,

ln(3 x 10^3/k1) = 62498/8.314[1/308 - 1/348]

rate constant (k1) at 35 oC = 181.46 (1/M.s)

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