So like I know that the balanced equation of my reaction is In the mitochondira

Question

So like I know that the balanced equation of my reaction is

In the mitochondira there is an R lactate dehydrogenase that unlike the cytoplasmic enzyme uses cytochrmoe c as an oxidizing agen and D lactate as a substrate. The prduct, pyruvate is the same for both enzymes. Given that the reduction portential of cytochrmoe c is 0.235 v at ph 7.

cyto-c[Fe+3] +e-= cyto-c[Fe+2].... and the reduction potential of pyruvate to F lactate is identical to that of L-Lactate.

Sooo......What are the change in G0?!??!

1. lac= pyruvate +2H+ +2e- = 0.185 V

2. cyto-c(Fe3+) +e-= cytc( Fe2+) =0.235 V

get my Eo'= ( 0.235-0.185)= 0.05V/mole-

How do I calculate my change Go'...... i know the equation is G= -nFE and that E= Eo' -RT/nFln ( red/ox) but what do I plug in to get my G cause i thought it would be 2( 0.05)/0.0592 = and I don't think that is right...

So basicaly what would the Go' be of this if we know the two half reactions... can you show me with steps

Explanation / Answer

E0 = 0.235-0.185 = 0.05V/mole

DG0 = -nFE0 = -2*96500*0.05 = - 9650 j = -9.65 kj

DG0 = -RTlnK

-9650 = -8.314*298 ln K

K = 49.15

E = E0 - 0.0591/n log K

E = 0.05-0.0591/2 log 49.15

E = 0.00001464 V

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.