the complete combustion of propane,C3H8(g),is represented by the equation: C3H8(

Question

the complete combustion of propane,C3H8(g),is represented by the equation: C3H8(g)+5O2(g)--->3CO2(g)+4H2O(l). delta Hdegree=-2220kJ ,
How much heat is evolved in the complete combustion of 2.50g C3H8(g)? the complete combustion of propane,C3H8(g),is represented by the equation: C3H8(g)+5O2(g)--->3CO2(g)+4H2O(l). delta Hdegree=-2220kJ ,
How much heat is evolved in the complete combustion of 2.50g C3H8(g)? C3H8(g)+5O2(g)--->3CO2(g)+4H2O(l). delta Hdegree=-2220kJ ,
How much heat is evolved in the complete combustion of 2.50g C3H8(g)?

Explanation / Answer

C3H8(g)+5O2(g)--->3CO2(g)+4H2O(l). delta Hdegree=-2220kJ ,

Weight of C3H8 = 2.50g , Molecular Weight of C3H8 = 44

Moles of C3H8 actually present = Weight of C3H8 / Molecular Weight of C3H8 = 2.50/44 = 0.0568mol

The enthalpy change for the combustion of 1 mol of C3H8 = -2220KJ

The enthalpy change for the combustion of 0.0568 mol(2.50g) of C3H8 =0.0568 X -2220KJ = -126.136KJ

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