Rank the molecules below in terms of their oxidation level, with the least oxidi

Question

Rank the molecules below in terms of their oxidation level, with the least oxidized labeled 1, and the most oxidized labeled 4. What drives the formation of the major product in the radical-chain chlorination of 2-methylbutane? the accessibility of the tertiary carbon radical intermediate, stabilized due to hyper conjugation the accessibility of the secondary carbon radical intermediate, stabilized due to hyper conjugation the accessibility of the primary carbon radical intermediate, stabilized due to hyper conjugation the accessibility of the primary carbon radical intermediate, stabilized due to light

Explanation / Answer

1) first one is the correct

2)

1 -D

2 -C

3-A

4-B

Explanation

1) this reaction follows free radical mechanism. There is posibility to form three types of free radicals . 10,20,30 radicals. But at 2 nd positon 2 mehtyl groups and one ethyl group is there. So no of possible hyperconjugations are 8. These are more compared to 20,30 hyper conjugations.

2) the secondary alcohol can be oxidized to a ketone

The ketone can even be oxidized to an ester

   Alkanes are less oxidised less reduced

Related Questions

Navigate

• Browse (All)
• Browse R
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.