1. When a 2.00-g sample of KBr is dissolved in water in a calorimeter that has a

Question

1. When a 2.00-g sample of KBr is dissolved in water in a calorimeter that has a total heat capacity of 0.7271 kJ?K-1, the temperature decreases by 0.460 K. Calculate the molar heat of solution of KBr.

2. Using the enthalpy of reaction for two reactions with ozone, determine the enthalpy of reaction for the reaction of chlorine with ozone.

(A) ClO(g) + O3(g) ---> Cl(g) + 2O2(g) (delta Hrxn = -122.8 kJ)

(B) 2O3(g) -->3O2(g) (delta Hrxn = -285.3 kJ)

(C) O3(g) + Cl(g) --> ClO(g) + O2(g) (delta Hrxn = ?)

3. Given these reactions:

X(s) + 0.5O2(g) --> XO(s) (delta H = -770.5 kJ)

XCO3(s) --> XO(s) + CO2(g) (delta H = +150.3 kJ)

What is the Hrxn for this reaction?

X(s) + 0.5O2(g) + CO2(g) --> XCO3(s)

1. When a 2.00-g sample of KBr is dissolved in water in a calorimeter that has a total heat capacity of 0.7271 kJ½K-1, the temperature decreases by 0.460 K. Calculate the molar heat of solution of KBr. 2. Using the enthalpy of reaction for two reactions with ozone, determine the enthalpy of reaction for the reaction of chlorine with ozone. (A) ClO(g) + O3(g) ---> Cl(g) + 2O2(g) (delta Hrxn = -122.8 kJ) (B) 2O3(g) -->3O2(g) (delta Hrxn = -285.3 kJ) (C) O3(g) + Cl(g) --> ClO(g) + O2(g) (delta Hrxn = ?) 3. Given these reactions: X(s) + 0.5O2(g) --> XO(s) (delta H = -770.5 kJ) XCO3(s) --> XO(s) + CO2(g) (delta H = +150.3 kJ) What is the Hrxn for this reaction? X(s) + 0.5O2(g) + CO2(g) --> XCO3(s) 4. Question 21 of 28 Consider these reactions. where M represents a generic metal. Use the information above to determine the enthalpy of the following reaction. 2M(s)+ 3Cl2(g ) right arrow 2MCl3(s) Hint Number kJ Previous Give Up & view Solution Check Answer Next Exit

Explanation / Answer

1.)

heat capacity = 0.7271 kJ / K

dT = 0.460 K

Q = Cp dT

Q = 0.7271 x 0.460

  = 0.3345 kJ

moles of KBr = 2.0 / 119 = 0.01681

molar heat = 0.3345 / 0.01681 = 19.90 kJ

molar heat of solution = 19.90 kJ

2)

A) ClO(g) + O3(g) ---> Cl(g) + 2O2(g) (delta Hrxn = -122.8 kJ) --------------> 1

(B) 2O3(g) ------------------>3O2(g) (delta Hrxn = -285.3 kJ)---------------------> 2

do it reverse for 1 and add equation to equation 2

Cl(g) + 2O2 ---------------> ClO + O3 , delta Hrxn = 122.8 kJ

2O3(g) ------------------>3O2(g) delta Hrxn = -285.3 kJ

-----------------------------------------------------------------------------

O3(g) + Cl(g) -------------> ClO(g) + O2(g) , delta Hrxn = - 162.5 kJ -------------------> answer

3)

X(s) + 0.5O2(g) --> XO(s) (delta H = -770.5 kJ) ---------------> 1

XCO3(s) --> XO(s) + CO2(g) (delta H = +150.3 kJ)------------->2

do the equation reverse and add to 1

X(s) + 0.5O2(g) + CO2(g) --> XCO3(s) , delta H = -770.5 - 150.3 =920.8 kJ

X(s) + 0.5O2(g) + CO2(g) --> XCO3(s) , delta H = - 920.8 kJ

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