(a) If we begin with an initial SO 2 Cl 2 pressure of 325 torr, what is the pres

Question

(a) If we begin with an initial SO2Cl2 pressure of 325 torr, what is the pressure of this substance after 74 s?
_________ torr
(b) At what time will the pressure of SO2Cl2 decline to one fourth its initial value?
______ s

By what factor will the pressure of sulfuryl chloride decrease after 4 half lives? Note: The answer wants this value: (325 torr)/value = final pressure after decay ________
value

The decomposition of sulfuryl chloride (SO2Cl2) is a first-order process. The rate constant for the decomposition at 660 K is 4.5 x 10-2 s-1. (a) If we begin with an initial SO2Cl2 pressure of 325 torr, what is the pressure of this substance after 74 s? _________ torr (b) At what time will the pressure of SO2Cl2 decline to one fourth its initial value? ______ s By what factor will the pressure of sulfuryl chloride decrease after 4 half lives? Note: The answer wants this value: (325 torr)/value = final pressure after decay ________ value

Explanation / Answer

  PART-1

Integrated 1st order equation:

ln(p) = ln(po) - kt,

ln(p) = ln(325 torr) - (0.045 /s) (74 s);

ln(p)=2.4538

, p = 11.6327 torr.

--------------------------------------------------------------------------------------------------------------------

PART-2

one fourth its initial value= 81.25torr

ln(81.25 torr) = ln(325 torr) - (0.045 /s) t;

0.045*t = ln(325)-ln(81.25)

0.045t=1.3862

t=30.80 sec

==========================================================================

The time to arrive at one sixteenth (1/16) of the the initial pressure it is four half lives

==>325/16 = 20.3125torr

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.