1. a. Calculate the molar mass of oxalic acid dihydrate H.CO 2H2O. Remember that
ID: 809058 • Letter: 1
Question
1. a. Calculate the molar mass of oxalic acid dihydrate H.CO 2H2O. Remember that the water molecules in a hydrate are part of the crystal structure and must be included when calculating molar mass. b. Use the molar mass to calculate the mass of oxalic acid dihydrate required to prepare 250 mL of 0.050 M oxalic acid solution. 2. Use the molar mass ofoxalic acid calculated in question 1(a) to calculate the concentration (M) of a solution prepared by dissolving 1.587 gof oxalic acid dihydrate in sufficient deionized water to prepare 250.0 mL ofsolution. 3. A 25.00 mL portion of the solution prepared in the preceding problem is titrated to the end point with 13.60 mL of sodium hydroxide. Use the balanced chemical equation for the titration reaction, the concentration and volume of the oxalic acid solution and the end point of the titration to calculate the concentration of the sodium hydroxide solution. 4. A 0.429 g portion ofa monoprotic (one reactable hydrogen ion) solid acid was dissolved in approximately 25 mL of water in an Erlenmeyer flask. After the addition of one drop of phenolphthalein indicator solution, the titrand solution was titrated with the standardized NaoH solution described in problem 3. The end point of the titration was 17.65 mL a) By using HA to represent the acid, write the balanced chemical equation for the titration reaction. b) Use the concentration of NaOH calculated in problem 3 and the endpoint volume to calculate the number of moles of the titrated acid. c) Use the mass of the weighed acid and the number of moles of the acid to calculate the molar mass of the acid. -87-Explanation / Answer
1 a.
molar mass of oxalic acid =90
0.025 X 25 = N2 X 13.6
N2 = 0.0459 N of NaOH
4. HA + NaOH --> H2O + NaA
N1V1 = N2V2
0.0459 X 17.65 = 25 X N2
N2 = 0.0324 N of Acid
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