Be sure to answer all parts. At 1024 Degrees C, the pressure of oxygen gas from

Question

Be sure to answer all parts.

At 1024 Degrees C, the pressure of oxygen gas from the decomposition of copper(II) oxide (CuO) is 0.490 atm:

4CuO(s) <==> 2Cu2 O(s)+O2(g)

(a) What is Kp for reaction? I got 0.49 for this but have been unable to get the other two.

(b) Calculate the fraction of CuO decomposed of 0.610 mole of it is placed in a 2.00 L flash at 1024 Degrees C.

(c) What would be the fraction if a 1.00 mole sample of CuO were used?

Please show work, I want to understand how to properly do the problem.

Explanation / Answer

a) Kp =     [0.49] [1]2

          -----------------------------=   3.55

        [0.610]4

b) 0.610 mole gives 0.490 mole of O2

.0.0610 X 79.54 = 48.5 gms gives 8 gms of O2 fraction decomposed = 8/48.5= 16.49x 100= 16.49%

c) if you use one mole the fraction would be 8/79.54= 10.05%

if you to do the above mentioned problem like this mentioned above you should know the basics of stoichiometry, mole fraction and Kp

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