tin Lecture Quiz 7 extra credit X C Chegg Study I Guided solution x VG Radiometr
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tin Lecture Quiz 7 extra credit X C Chegg Study I Guided solution x VG Radiometric dating of fossils is x noah C secure https:/ moodle.Sonoma.ed attempt 277539&page; 1 u/B/mod/quiz/attempt.php? Apps J, YouTube to mp3 Co YouTube a Amazon.com: Onlin S Sonoma State Univ D Web Portal Login S Seawolf Scheduler M Sign In I McGraw-H. Other Bookmarks Messages Noah BIOL-110-17-SP: Biological Inquiry (meta) N Home Dashboard Events My Courses da This course C Get Help Spring 2017 BIOL M-BIOL-110-17-SP Topic 15 Lecture Quiz 7 extra credit Question 7 A population of butterflies is observed in a large meadow with abundant food and water. When observations E Quiz navigation Not yet answered began (time 0), the population size was estimated to be 3000 individuals. After the first six months, it was observed that the average number of births was 228 per 1000 individuals. The average number of deaths was Marked out of 128 per 1000 individuals. These rates did not change over the observation time. Based on these data, what is the 3 4 5 6 7 P Flag question net growth rate (r) of this population? Select one a. 0.0 Finish attempt b. 0.08 C. 0 d. 0.2 e. 0.5 Question 8 Carrying capacity Not yet answered Select one: Marked out of a, is the reduction in birth rates a population experiences during exponential growth,Explanation / Answer
Growth rate is defined as total increase in population per unit population in unit time
Formula. = (no. Of births - no. Of deaths)in one year / total population
No of births per 1000 individuals in 6 months = 228, then for 3000 individuals , total births=228x3=684
No. Of births in total population in one year = 684x2 = 1368
No. Of deaths per 1000 individuals in 6 months=128., for 3000 individuals , total deaths= 128x3=384
No. Of deaths in total population in one year= 384x2= 768. Growth rate = total births- total deaths/total population = 1368-768/3000 = 0.2
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