A reaction vessel at 27 ?C contains a mixture of SO2(P= 2.90atm ) and O2(P= 1.00

Question

A reaction vessel at 27 ?C contains a mixture of SO2(P= 2.90atm ) and O2(P= 1.00atm ). When a catalyst is added the reaction 2SO2(g)+O2(g)?2SO3(g) takes place. At equilibrium the total pressure is 3.65atm.

Part A

Find the value of Kc.

Express your answer using two significant figures.

A reaction vessel at 27 ?C contains a mixture of SO2(P= 2.90atm ) and O2(P= 1.00atm ). When a catalyst is added the reaction 2SO2(g)+O2(g)?2SO3(g) takes place. At equilibrium the total pressure is 3.65atm.

Part A

Find the value of Kc.

Express your answer using two significant figures.

Explanation / Answer

                       2SO2   +O2   --->2SO3
initial                2.9         1

at equilibrium    2.9-2x     1-x           2x

Total pressure = 2.9-2x+1-x +2x =3.9-x
3.9-x =3.65
x=0.25

p SO2 = 2.9-2x = 2.9-2*0.25 =2.4 atm
PO2 = 1-x = 1-0.25 = 0.75 atm
pSO3 = 2x = 2*0.25 =0.5 atm

Kp = (pSO3)^2 / {(PSO2)^2 *PO2}
    = 0.5^2 / (2.4^2 * 0.75)
    = 0.056

use:
Kp= Kc *(R*T)^deltan    {delta n =2-3=-1 and T =273+27=300K}
0.056 = Kc* (8.314*300)^-1
Kc= 144.34

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