Many handheld laser pointers emit 650 nm light. What is the frequency of this li
ID: 805377 • Letter: M
Question
Many handheld laser pointers emit 650 nm light. What is the frequency of this light?
Select one:
a. 2.0 X 102 Hz
b. 5.1 X 10-3 Hz
c. 2.2 X 10-15 Hz
d. 4.6 X 1014 Hz
e. 1.5 X 106 Hz
Place the following regions of the electromagnetic spectrum in order from longest to shortest wavelength.
Select one:
a. microwave>radio>uv>visible>gamma
b. uv>visible>microwave>radio>gamma
c. gamma>microwave>radio>visible>uv
d. visible>gamma>radio>uv>microwave
e. raido>microwave>visible>uv>gamma
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Question text
All of the following statements are false EXCEPT
Select one:
a. the wavelength of light is directly proportional to its frequency.
b. the frequency of light is directly proportional to the speed of light (in a vacuum).
c. the wavelength of light is directly proportional to the speed of light (in a vacuum).
d. the frequency of light is inversely proportional to its energy.
e. the energy of a photon of light is inversely proportional to its wavelength.
Which of the following electronic transitions would emit the lowest energy photon?
Select one:
a. n = 2 to n = 1
b. n = 3 to n = 2
c. n = 5 to n = 2
The Schrodinger wave equation
Select one:
a. proves that photons are particles.
b. can be solved to find the probability of finding an electron in a region of space.
c. proves electrons have positive and negative spins.
d. calculates the precise position and momentum of an electron at any given time.
Which of the following sets of quantum numbers refers to a 3p orbital?
Select one:
a. n=3, L=0, mL=0, ms=+1/2
b. n=3, L=3, mL=-2, ms=+1/2
c. n=3, L=3, mL=3, ms=+1/2
d. n=3, L=2, mL=1, ms=+1/2
e. n=3, L=1, mL=-1, ms=+1/2
d. n = 1 to n = 2
e. n = 5 to n = 4
Explanation / Answer
1.wavelength (?) = speed of light (c) divided by the frequency (f)
where c = 299,792,458 meters per second (m/s)
? = c / f
650nm = 650E-9 m = ?
650E-9m = (299,792,458 m/s) / f
f = (299,792,458 m/s) / 650E-9m
f = 4.6122E14 Hz
f = 461.2192E12 Hz
2)e
3)d
4)
5)e
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