The integrated rate law allows chemists to predict the reactant concentration af

Question

The integrated rate law allows chemists to predict the reactant concentration after a certain amount of time, or the time it would take for a certain concentration to be reached.

The integrated rate law for a first-order reaction is:
0.693k

Now say we are particularly interested in the time it would take for the concentration to become one-half of its inital value. Then we could substitute [A]o/2afor [A] and rearrange the equation to: t 1/2=  .693/k
567452t1/2
This equation caculates the time required for the reactant concentration to drop to half its initial value. In other words, it calculates the half-life.

Explanation / Answer

part-A

HALF LIFE=0.693/K

=0.693/5.20*10^-4

=1332.69 SECONDS

PART-B

K=(2.303/t) log a/(a-x)

=(2.303/7*60) log a/a/2

=1.65*10^-3 sec^-1

part-c

K=(2.303/t) log a/(a-x)
7.50*10^-3=(2.303/t) log(a/a/18)

t=385.45 seconds

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