1. What is the molarity of a nitric acid solution prepared by diluting 250.0 mL

Question

1.     What is the molarity of a nitric acid solution prepared by diluting 250.0 mL of 6.00 M HNO3 to a total volume of 2.50 L? A) 0.0600 M B) 0.250 M C) 0.600 M D) 2.50 M E) 6.00 M

2.     What is the molarity of aqueous silver nitrate if 50.0 mL of AgNO3 reacts with 25.0 mL of 0.100 M K2CrO4? 2 AgNO3(aq)   +   K2CrO4(aq)   ?   Ag2CrO4(s)   +   2 KNO3(aq)   A) 0.0250 M B) 0.0500 M C) 0.100 M D) 0.200 M E) 0.400 M

3.     What acid and base are neutralized to give potassium nitrate salt? A) HCl(aq) and KOH(aq) B) HNO3(aq) and KOH(aq) C) HNO3(aq) and KNO3(aq) D) HOH(aq) and KNO3(aq) E) none of the above

4.    In the following reaction, which reactant is a Br

Explanation / Answer

1) M1V1 = M2V2

0.25 * 6 = 2.5 * M2

M2 = 0.600 M

option (C)

2) 25.0 ml of 0.1 molar = 2.5 * 10^-3 moles

reacts with 50 ml AgNO3

molarity will be = 0.05M

option B

3)HNO3 + KOH----------> KNO3 + HOH

Potassium Nitrate is obtained

option (b)

4) NaH2PO4 is the proton donor. hence brownsted Lowry acid.

5) M1V1 = M2V2

V2 = 8.33 ml

6) The solution is slightly ionised as it does not conduct electricity

7) H2CO3 is a weak electrolyte.

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