The Energy needed for the following process is 1.960x 10^4 kJ/mol: Li(g) rightar

Question

The Energy needed for the following process is 1.960x 10^4 kJ/mol:

Li(g) rightarrow Li3+ (g) + 3e - If the first ionization energy of lithium is 5.20 times 102 kJ/mol, calculate the second ionization energy of lithium-that is, the energy' required for the process : Li+ (g) rightarrow L2+ (g) + e- A hydrogen-like ion is an ion containing only one electron. The energies of the electron in a hydrogen-like ion are given by En = -(2.18 times 10-18 J) z2 (1/n2) where En is the energy of the electron in the n hydrogen-like ion, n is the principal quantum number and, Z is the atomic number of the element. Second ionization energy of lithium: (Enter your answer in scientific notation) which statement describes boron?

Explanation / Answer

E = - 2.18*10^-18*(9/1) = 19.62*10^-18 J = 19.62*10^-21 Kj/mol

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