1-Describe how would you prepare 200.00mL of 0.150M sodium nitrate from the soli
ID: 795792 • Letter: 1
Question
1-Describe how would you prepare 200.00mL of 0.150M sodium nitrate from the solid? show calculation
2- How woud you make 150.00mL OF 0.300M sulfuric acid from a stock bottle that is 10.0 M? show calculation
3- What is the new molarity if 25.00mL OF 8.00M hydrochloric acid is diluted to 350.0mL?
4- WHAT effect would the following have on your determined absorbance measurement of a solution. (too high, too low, or unchanged)?
A) bubbles in the cuvette
B) fingerprints that reflect light
C) fingerprints on the cuvette that absorb at your chosen wavelength.
Explanation / Answer
Molarity M = no of moles in solution/volume in litres
1) 0.15 = n/0.2
n = 0.03 moles
weight of sodium nitrate req = 0.03*85 = 2.55gms
so 2.55gms of sodium nitrate is dissolved in 200ml of water
2)V = 150*0.3/10 = 4.5 ml
4.5 ml of 10M stock bottle solution is diluted 150 ml by adding water
3)M = 25*8/350 = 0.57M
Final molarity will be 0.57M
4) A) too low
B) too hiigh
C)unchanged
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