The addition of 100 g of a compound B to 750 g of CCl 4 lowered the freezing poi
ID: 794929 • Letter: T
Question
- The addition of 100 g of a compound B to 750 g of CCl4 lowered the freezing point of a solvent by 10.5 K. Calculate the molar mass of the compound if the Kf, CCl4=30K kg mol-1.
Explanation / Answer
Freezing point depression = Delta Tf = 10.5 K
Molality = Delta Tf/Kf
= 10.5/30 = 0.35m
Mass of CCl4 = 750 g = 0.75 kg
Moles of compound = molality x mass of CCl4 in kg
= 0.35 x 0.75 = 0.2625 mol
Mass of compound = 100 g
Molar mass of compound = mass/moles of compound
= 100/0.2625
= 380.95 g/mol = 381 g/mol
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