Standardization of NaOH Titrant. From the mass of standard acid used,calculate t

Question

Standardization of NaOH Titrant. From the mass of standard acid used,calculate the number of moles of NaOH necessary for neutralization. From thisresult and the titrant volume delivered, determine the concentration of the NaOH titrant. Report the average of your three best results and the % deviation.

NaOH is .1 M

So instead of 3, say I have .31g of KHC8H4O4 and .33g

For the moles of NaOH

X * .1 * 204.2 = . 31g

that would be .0016 moles, sound right?

Can someone help with the rest if that's right?



Standardization of NaOH Titrant. From the mass of standard acid used,calculate the number of moles of NaOH necessary for neutralization. From thisresult and the titrant volume delivered, determine the concentration of the NaOH titrant. Report the average of your three best results and the % deviation.

NaOH is .1 M

So instead of 3, say I have .31g of KHC8H4O4 and .33g

For the moles of NaOH

X * .1 * 204.2 = . 31g

that would be .0016 moles, sound right?

Can someone help with the rest if that's right?

Explanation / Answer

The X u calculated should be volume as volume * molarity gives moles of NaOH for netralization.

So, X = 0.00152 L = 1.52 ml

Now you were asked to calculate avg of 3 readings and their deviation.

So, take 3 readings .

Avg = (X1+X2+X3)/3 ; say Avg = X

Now for deviation,

calculate square of (X-Xi) for all the data set.

T1 = (X-X1)^2 , T2 = (X-X2)^2 , T3 = (X-X3)^2

Deviation = sqrt [ (T1+T2+T3)/(N-1) ] ; N = 3, since data taken is 3

Hope this is what you were looking for...

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