The following reaction, sometimes used in the laboratory to generate small quant

Question

The following reaction, sometimes used in the laboratory to generate small quantities of oxygen gas, has ?G?= ?224.4kJ/mol at 25 ?C:
2KClO3(s)?2KCl(s)+3O2(g) Use the following additional data at 25 ?C to calculate the standard molar entropy S? of O2 at 25 ?C: ?H?f(KClO3)= ?397.7kJ/mol , ?H?f(KCl)=?436.5kJ/mol , S?(KClO3)= 143.1J/(K?mol) , and S?(KCl)=82.6J/(K?mol). The following reaction, sometimes used in the laboratory to generate small quantities of oxygen gas, has ?G?= ?224.4kJ/mol at 25 ?C:
2KClO3(s)?2KCl(s)+3O2(g) The following reaction, sometimes used in the laboratory to generate small quantities of oxygen gas, has ?G?= ?224.4kJ/mol at 25 ?C:
2KClO3(s)?2KCl(s)+3O2(g) The following reaction, sometimes used in the laboratory to generate small quantities of oxygen gas, has ?G?= ?224.4kJ/mol at 25 ?C:
2KClO3(s)?2KCl(s)+3O2(g) The following reaction, sometimes used in the laboratory to generate small quantities of oxygen gas, has ?G?= ?224.4kJ/mol at 25 ?C:
2KClO3(s)?2KCl(s)+3O2(g) Use the following additional data at 25 ?C to calculate the standard molar entropy S? of O2 at 25 ?C: ?H?f(KClO3)= ?397.7kJ/mol , ?H?f(KCl)=?436.5kJ/mol , S?(KClO3)= 143.1J/(K?mol) , and S?(KCl)=82.6J/(K?mol). The following reaction, sometimes used in the laboratory to generate small quantities of oxygen gas, has ?G?= ?224.4kJ/mol at 25 ?C:
2KClO3(s)?2KCl(s)+3O2(g) Use the following additional data at 25 ?C to calculate the standard molar entropy S? of O2 at 25 ?C: ?H?f(KClO3)= ?397.7kJ/mol , ?H?f(KCl)=?436.5kJ/mol , S?(KClO3)= 143.1J/(K?mol) , and S?(KCl)=82.6J/(K?mol).

Explanation / Answer

Note that both gibbs free energy of formation and enthalpy of formation for oxygen in standard state are zero (by definition).

So you have enough information to compute the change in enthalpy due to reaction. With given ?Gr

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