Part A 0.50 g of hydrogen chloride ( H C l ) is dissolved in water to make 7.0 L

Question

Part A 0.50g  of hydrogen chloride (HCl) is dissolved in water to make 7.0L  of solution. What is the pH of the resulting hydrochloric acid solution?
Part B 0.65g  of sodium hydroxide (NaOH) pellets are dissolved in water to make 6.5L  of solution. What is the pH of this solution? Express the pH numerically to two decimal places.



Part A 0.50g  of hydrogen chloride (HCl) is dissolved in water to make 7.0L  of solution. What is the pH of the resulting hydrochloric acid solution?
Part B 0.65g  of sodium hydroxide (NaOH) pellets are dissolved in water to make 6.5L  of solution. What is the pH of this solution? Express the pH numerically to two decimal places.



Part B 0.65g  of sodium hydroxide (NaOH) pellets are dissolved in water to make 6.5L  of solution. What is the pH of this solution?

Explanation / Answer

0.50gm hcl=0.5/36.5mole=0.0137mole HCl

molarity of HCl = 0.0137 mol HCl / 7.0 L = 1.957*10^-3M HCl

1.957*10^-3M HCl = 1.957*10^-3M H3O+: pH = -log(1.957*10^-3M) = 2.7

part B :

0.65gm NaOH=0.65/40mole=0.01625mole

molarity of NaOH=0.01625M/6.5L=2.5*10^-3 M

2.5*10^-3 M NaOH= 2.5*10^-3 M OH-

pOH=-log(2.5*10^-3 M)=2.6

pH=14-pOH=14-2.6=11.39

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