1-butanol + hydrobromic acid -----------> 1-bromobutane + H2O 1-butanol hydrobro

Question

1-butanol + hydrobromic acid -----------> 1-bromobutane + H2O

1-butanol                        hydrobromic acid                          1-bromobutane + H2O

Bp-118 C                         Den 1.49                                          Bp-101.6 C

Den .810                          MW 80.9                                          Den. 1.275

If you were to react 48mmol of 1-butanol with 66mmol of aqueous hydrobromic acid and you obtained 3.7g of 1-bromobutane what is the (show Calculations)

A) theoretical Yield

B) Limiting Reagent

C) Percent Yield

Explanation / Answer

in General 1mole of 1-butanol reacts with 1 mole of hydrobromic acid yielding 1 mole of 1-bromobutane.
As there are 44 mmoles of 1-butanol and 66mmoles of hydrobromic acid.
A) As 1-butanol is totally consumed It is the limiting reagent.

B) Theortically 22 mmloes of hydrobromic acid will be left and 44 mmoles of 1-brombutane will be prduced.

C)Experimentally produced is 3.7/137=27 mmoles of 1bromobutane.So yield is 27/44 * 100=61%

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