1) Aspirin (C 9 H 8 O 4 ) is synthesized by mixing salicylic acid (C 7 H 6 O 3 )
ID: 792290 • Letter: 1
Question
1) Aspirin (C9H8O4) is synthesized by mixing salicylic acid (C7H6O3) with excess acetic anhydride (C4H6O3). The balanced equation is:
C7H6O3 + C4H6O3 ------------> C9H8O4 + C2H4O2
Molar mass/ g.mol^-1
C2H4O2 60
C4H6O3 102
C7H6O3 138
C9H8O4 180
When 2.0g of salicylic acid is mixed with excess acetic anhydrude, 1.7g of aspirin is collected . What is the percent yield for this reaction?
2) Starting with 4.3 L if 0.58 M Na2CO3(aq) what volume of this solution is needed to prepare 250 mL of 0.20 M Na2CO3(aq) solution?
3) If 26.32 mL of .100 M H2SO4 is exactly neutralized by 34.56 of NaOH solution, what is the molar concentration?
4) A solution is prepared by dissolving 3.422g of Al2(SO4)3, molar mass 342.2 g.mol^-1, in water to obtain 0.100 L of solution. What is the molar concentration of sulfate ion in this solution?
Please explain! Step by step if possible! Thank you!
Explanation / Answer
1) by the given reaction
C7H6O3 + C4H6O3 ------------> C9H8O4 + C2H4O2
1 mole of salicylic acid should give 1 mole of aspirin
that is 138 g of salicylic acid should give 180 g of aspirin
let 2 g of salicylic acid give x g of aspirin
then x= 2 *180/138 = 2.61 g
so 2 g of salicylic acid should give 2.61 go aspirin
but give only 1.7 g aspirin is obtained
so percentage yield= 1.7/ 2.61 x100
percentage yield is 63.13 %
2) Final requirement is 250 mL of 0.20 M of Na2CO3 solution
moles = molarity x volume /1000
= 0.20 x 250/1000
moles=0.05
these moles should come from 0.58 M Na2C03
so conc=moles x 1000/volume
0.58= 0.05x1000/volume
volume= 86.02 ml
3)
2NaOH + H2SO4 -> Na2SO4 + 2H20
for H2SO4 Normality = molarity x 2
consider N1V1=N2V2
that is 0.2 x 26.32 = 34.56 x N2
N2= 0.15 N
for NaOH molarity = normality
Molarity = O.15 M
4) Given mass=3.422 g and M.w = 342.2 g and volume=0.1 L
conc= mass /M.W x Volume(L)
= 3.422 /342.2 x0.1
conc= 0.1 M
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