using only the following information delta H Formation for NO(g)=+90.4 kj/mol de
ID: 791616 • Letter: U
Question
using only the following information
delta H Formation for NO(g)=+90.4 kj/mol
delta H = -56.6 kj/mol for the reaction NO +1/2 O2----NO2
determine delta H formation for NO2
b) using on the answer above and the following
delta H =-283 kj/mol for reaction CO + 1/2 O2 ------CO2
determine delta H for the reaction 4CO + 2NO2 ------4CO2 +N2
C)a 10L vessal contains 5.0atm of CO and 3 atm of NO2 at 25 C. How much heat in joules will be liberated if this is allowed to react to completion according to the reaction in part b.
d) in a sperate experiment using a very large reaction vessal with a movable piston 6 moles of CO2 reacts completely with 3 moles of nitrogen gas according to the following equation at 25 C and with a constant external pressure of 2 atm
4CO2 + 2N ------4CO +2NO2
calculate delta U,q,w for this reaction
Explanation / Answer
a)
delta H of reaction= delta H formation of NO2 -delta H Formation for NO(g
-56.6 kj/mol =delta H formation of NO2-90
delta H formation of NO2= 33.4 KJ/mol
b) delta H =-283 kj/mol for reaction CO + 1/2 O2 ------CO2
-283 =delta H CO2-delta H CO ......................(1)
delta H for the reaction 4CO + 2NO2 ------4CO2 +N2
delta H= 4*(delta H CO- delta H CO) -2*delta H NO2
from 1 -283 =delta H CO2-delta H CO and from a delta H formation of NO2= 33.4 KJ/mol
using
delta H =4*(283)-2*33.4
= 1098.6 KJ/mol
c)
no. of moles of NO2 = 3*10/0.082*298= 1.226 moles
no. of moles of CO =5*10/0.0821*298 = 2.043 moles
reaction is 4CO + 2NO2 ------4CO2 +N2
moles reacted =2.04/2 =1.021 moles
hence heat of reaction = 1.021*1098.6 =1122.22 KJ
d)
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