Rank the following solutions in order of increasing osmotic pressure: 2.0 m CH 3

Question

Rank the following solutions in order of increasing osmotic pressure: 2.0 m CH3OH, 1.0 mBa(NO3)2, 3.0 m KCl, 3.0 m C6H12O6

A. CH3OH < Ba(NO3)2 = C6H12O6 < KCl B. Ba(NO3)2 < CH3OH < KCl = C6H12O6
C. CH3OH < Ba(NO3)2 < C6H12O6 < KCl D. C6H12O6 = KCl < CH3OH < Ba(NO3)2
E. KCl < CH3OH < Ba(NO3)2 < C6H12O6 Rank the following solutions in order of increasing osmotic pressure: 2.0 m CH3OH, 1.0 mBa(NO3)2, 3.0 m KCl, 3.0 m C6H12O6
Rank the following solutions in order of increasing osmotic pressure: 2.0 m CH3OH, 1.0 mBa(NO3)2, 3.0 m KCl, 3.0 m C6H12O6
CH3OH < Ba(NO3)2 = C6H12O6 < KCl Ba(NO3)2 < CH3OH < KCl = C6H12O6
CH3OH < Ba(NO3)2 < C6H12O6 < KCl C6H12O6 = KCl < CH3OH < Ba(NO3)2
KCl < CH3OH < Ba(NO3)2 < C6H12O6 A. CH3OH < Ba(NO3)2 = C6H12O6 < KCl B. Ba(NO3)2 < CH3OH < KCl = C6H12O6
C. CH3OH < Ba(NO3)2 < C6H12O6 < KCl D. C6H12O6 = KCl < CH3OH < Ba(NO3)2
E. KCl < CH3OH < Ba(NO3)2 < C6H12O6

Explanation / Answer

Increase depends on number of moles of particles

2.0 m CH3OH = 2.0 m particles

1.0 m Ba(NO3)2 = 3.0 m particles as it dissociates to give Ba2+ + 2NO3-

3.0 m KCl = 6.0 m particles as KCl = K+ + Cl-

3.0 m C6H12O6 = 3m partices

So order is CH3OH < Ba(NO3)2 = C6H12O6 < Kcl

So answer is A

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