The following is a question from my practice exam for my organic chemistry lab m

Question

The following is a question from my practice exam for my organic chemistry lab midterm, please help!

Acetanilide was prepared according to the reaction shown above. Aniline (2.12 g), Dl water (15 mL), and acetic anhydride (2.5 mL) were stirred together in an Erlenmeyer flask. Heat was given off as the reaction proceeded. After the reaction was allowed to run for an hour, the reaction was neutralized. How many mL of 2.5 M aqueous NaHCO3 would you add if you wanted to add a 10-fold excess? Show your calculations below.

Explanation / Answer

moles of aniline =2.12/99.13=0.0213 moles

moles of acetic anhydride =2.5*1.082/102.09=.0264 moles ( mass=volume*density)

here aniline is limiting reagent so moles of acetic acid formed is equal to moles of aniline

so moles of acetic acid formed equal to 0.0213 moles so moles of NaHCO3 should be added is moles of acetic acid so

moles for 10 fold excess is 10*moles of acetic acid =10*0.0213=0.213 moles volume = C*moles (C is concentration)

volume =2.5*0.213=0.5325lit=532.5ml

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