Problem 3.38 H C l has a rotational constant of 10.59 c m ? 1 and a vibrational
ID: 791120 • Letter: P
Question
Problem 3.38 HCl has a rotational constant of 10.59 cm?1 and a vibrational constant of 2991 cm?1. Part A Find the temperature, if there is one, at which the J = 0 and J = 1 rotational states have the same population. Express your answer using two decimal places.________________________ K
Part B
Find the temperature, if there is one, at which the = 0 and = 1 states have the same population.
27.74 K
0 K
55.48 K
There is no finite temperature Problem 3.38 Problem 3.38 HCl has a rotational constant of 10.59 cm?1 and a vibrational constant of 2991 cm?1. HCl has a rotational constant of 10.59 cm?1 and a vibrational constant of 2991 cm?1. HCl has a rotational constant of 10.59 cm?1 and a vibrational constant of 2991 cm?1. Part A Find the temperature, if there is one, at which the J = 0 and J = 1 rotational states have the same population. Express your answer using two decimal places.
________________________ K
Part A Find the temperature, if there is one, at which the J = 0 and J = 1 rotational states have the same population. Express your answer using two decimal places.
________________________ K
________________________ K
________________________ K
Part B
________________________ K
Explanation / Answer
(A) The answer is: 27.74 K
Boltzmann distribution for rotational energy levels:
N(J)/N(0) = (2J + 1) exp[-(BhcJ(J + 1)/kT]
where N is population, B is rotational constant in cm-1, h is Planck constant, c is speed of light in cm/s, k
is Boltzmann constant and T is temperature
For J = 1 and N(1) = N(0)
N(1)/N(0) = (2 x 1 + 1) x exp[-10.59 x 6.626 x 10^(-34) x 2.998 x 10^10 x 1 x (1 + 1)/(1.3806 x 10^(-23) x T)]
1 = 3 x exp(-30.466/T)
-30.475/T = ln(1/3) = -1.0986
Temperature T = 27.74 K
(B) The answer is: There is no finite temperature
Boltzmann distribution for vibrational energy levels:
N(v)/N(0) = exp[-(E(v) - E(O))/kT]
where N is population, E is vibrational energy level, k is Boltzmann constant and T is temperature
For v = 1:
N(1)/N(0) = exp[-(E(1) - E(O))/kT]
= exp(-hcw/kT) (where w is vibrational constant)
= exp[-6.626 x 10^(-34) x 2.998 x 10^10 x 2991/(1.3806 x 10^(-23) x T)]
= exp(-4303.6/T) which is less than 1 for all positive values of T
Thus there is no finite temperature T for which N(1)/N(0) = 1
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.