Kinetic data collected at 298K for following reaction: 2I(aq) ^- + S2O8(aq) ^-2
ID: 790703 • Letter: K
Question
Kinetic data collected at 298K for following reaction:
2I(aq) ^- + S2O8(aq) ^-2 >>>>I2(aq) +2SO4(aq)^-2
2 Iodine Iodine 2
[I^-] moles/liter
0.125
0.125
[S2O8^-2] moles/liter
0.050
0.150
Rate,moles/minute
0.015
0.044
What is the rate law expression with respect to S2O8(aq)^-2?
Explain in steps in details
Explanation / Answer
Rate1 = K[I-]^m[S2O8]^n
0.015 =K[0.125]^m[0.05]^n................1
Rate 2 = K[I-]^m[S2O8]^n
0.044 = K [0.125]^m[0.15]^n.................2
if we do rate1/rate2
0.015/0.13 = (0.05/0.15)^m
0.34 = (0.34)^n
n= 1
oder of reaction w.r.t. S2O8 ion is 1
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