Given the enthalpies of reaction S(s) + O2(g) ?SO 2 (g) ?H o = -297 kJ 2S(s) + 3

Question

Given the enthalpies of reaction
S(s)  +   O2(g)   ?SO2(g) ?Ho = -297 kJ

2S(s)  + 3 O2(g)    ?  2 SO3(g) ?Ho = -791 kJ


Calculate the enthalpy change (?H) for the reaction:
2 SO2(g)  +   O2(g)   ?   2 SO3(g) Question options: PLEASE EXPLAIN
-494 kJ -197 kJ
1088 kJ Given the enthalpies of reaction
S(s)  +   O2(g)   ?SO2(g) ?Ho = -297 kJ

2S(s)  + 3 O2(g)    ?  2 SO3(g) ?Ho = -791 kJ


Calculate the enthalpy change (?H) for the reaction:
2 SO2(g)  +   O2(g)   ?   2 SO3(g) Given the enthalpies of reaction
S(s)  +   O2(g)   ?SO2(g) ?Ho = -297 kJ

2S(s)  + 3 O2(g)    ?  2 SO3(g) ?Ho = -791 kJ


Calculate the enthalpy change (?H) for the reaction:
2 SO2(g)  +   O2(g)   ?   2 SO3(g) -494 kJ -197 kJ
1088 kJ -494 kJ -197 kJ 1088 kJ -494 kJ -197 kJ
1088 kJ

Explanation / Answer

2SO2(g)? 2S(s) + 2O2(g)    ?Ho = +297*2 kJ

2S(s) + 3 O2(g) ? 2 SO3(g) ?Ho = -791 kJ

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2 SO2(g) + O2(g) ? 2 SO3(g)   ?Ho= +(297*2)-791= -197KJ

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