Acid spills can be dealt with by neutralizing the acid with a sodium bicarbonate

Question

Acid spills can be dealt with by neutralizing the acid with a sodium bicarbonate solution. What volume in mL of 2.00 M sodium bicarbonate solution is needed to neutralize 25.0 mL of 4.00 M HCl?

The reaction proceeds as follows: HCl(aq) + NaHCO3(aq) -> H2O(l) + CO2(g) + NaCl(aq)

The volume of 2.00 M sodium bicarbonate solution needed to neutralize 25.0 mL of 4.00 M HCl is

_____x10^_____mL. Please Explain

Acid spills can be dealt with by neutralizing the acid with a sodium bicarbonate solution. What volume in mL of 2.00 M sodium bicarbonate solution is needed to neutralize 25.0 mL of 4.00 M HCl? The reaction proceeds as follows: HCl(aq) + NaHCO3(aq) -> H2O(l) + CO2(g) + NaCl(aq) The volume of 2.00 M sodium bicarbonate solution needed to neutralize 25.0 mL of 4.00 M HCl is x 10^ mL. Please Explain

Explanation / Answer

let the volume be v.

so one mole of acid reacts with one mole of the base.

hence balancing the number of moles,

M1V1=M2V2

or 2*v=25*4

or v=50 mL

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