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ID: 787056 • Letter: H
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Which one of the following best represents the predicted approximate chemical shift and coupling for the hydrogen(s) indicated with the arrow? 3.00 ppm, triplet 5.00 ppm, triplet 5.40 ppm, multiplet 3.00 ppm, doublet 1.00 ppm, doublet IR absorption signals of alcohols are typically broad. However, IR spectra of gaseous samples show sharp peaks. Briefly explain why. In gaseous samples, no ionic bonding is possible, and the signal becomes sharp. The statement is incorrect. IR spectra are identical for liquid and gaseous compounds. In gaseous samples, no hydrogen bonding is possible, and the signal becomes sharp. Broad signals of alcohols are due to ionic bonding associated with the O-atom. Broad signals of alcohols are due to hydrogen bonding associated with the O-H group. Which compound below would give rise to 5 signals in the proton NMR spectrum and 7 signals in the carbon NMR spectrum? (Assume you can separate and see all peaks.) I II III IV None of the above. A compound with the molecular formula C1OH14 gave the following 1H NMR spectrum: doublet, delta 1.2 singlet, delta 2.3 septet, delta 2.8 multiplet, delta 7.1 A possible structure for the compound is:Explanation / Answer
9) 3ppm triplet
108)4th option
83) 2nd option
125)Broad signals of alcohols are due to hydrogen bonding associated with the O-H group. In gaseous samples, no hydrogen bonding is possible, and the signal becomes sharp
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