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1. The molar heat of vaporization for water is 44.01 kJ/mol at 298 K and 40.79 k

ID: 785789 • Letter: 1

Question

1.     The molar heat of vaporization for water is 44.01 kJ/mol at 298 K and 40.79 kJ/mol at 373K. Write a thermodynamic cycle explaining how you would calculate the value at 298 K if you knew the value at 373K and show what other data you would need to compute it. Give a qualitative explanation for the difference between these values.

The molar heat of vaporization for water is 44.01 kJ/mol at 298 K and 40.79 kJ/mol at 373K. Write a thermodynamic cycle explaining how you would calculate the value at 298 K if you knew the value at 373K and show what other data you would need to compute it. Give a qualitative explanation for the difference between these values.

Explanation / Answer

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