Question
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NIcole, a botanist, discovered a monoprotic acid in an extract from a tropical plant and performed the following experiments: She titrates 100.0 mL of the plant extract with 0.100 M NaOH. The titration midpoint is reached at 25.6 mL of NaOH. The pH at this point is 3.59. By evaporating the solvent from the extract, she determines that there is only 0.124 g of acid per 10.0 mL of plant extract. What is the Ka value for the acid? What is the pH of the plant extract? What is the pH after the following additions of 0.100 M NaOH: 30.0 mL, 51.2 mL, 55.0 mL ? What is the molecular weight of the plant extract?
Explanation / Answer
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