1. a) Write a net ionic equation for the precipitation of lead (II) iodide. b) W

Question

1.

a) Write a net ionic equation for the precipitation of lead (II) iodide.

b) Write the net ionic equation for copper+silver nitrate

c)Write an equation for the combustion of C4H10

d)for part b and c identify substanceoxidized, substance reduced, oxidizing agentand reducing agent

2.

a)How many molcules of sugar (C6H12O6)are contained in 2.50grams of C6H12O6

b)How many atomsof Hydrogen are contained in 2.50grams of C6H12O6

c)How manygrams of CO2 will be produced from the combustion of 2.50grams of C6H12O6

3. If 8.00grams of Pb(NO3)2 reacts with 2.67grams of AlCL3

a) calculate the theoretical yield(grams) of PbCl2 (s)

b) Identity the limiting and excess reactant

c) How many grams of excess reactant will remain?

d) If 5.55grams of PbCl2 is actually recoveredin the lab, what is the % yield?

Explanation / Answer

1.)

Pb(NO3)2(aq) + 2KI(aq) --> PbI2(s) + 2KNO3(aq)

If we eliminate the spectator ions in this equation we can express the precipitation reaction as a net ionic equation.       

Pb 2+ (aq) + 2I -  (aq) --> PbI2 (s)

the nitrate will be a spectator ion (it is always soluble).

Cu + 2AgNO3 --> Cu(NO3)2 + 2Ag
complete ionic
Cu + 2Ag^+ + 2NO3^- --> Cu^2+ 2NO3^- + 2Ag
Net ionic
Cu + 2Ag^+ --> Cu^2+ 2Ag

Cu and Ag are (s)
2Ag^+ Cu^2+ are (aq)

2C4H10 + 13O2 --> 8CO2 + 10H2O

2.)

a.)mol wt of sugar=180 and given weight =2.5 grams using avagadro numbver and calculating we get 8.33*10^23

b.)atoms of hydrogen in 2.5 grams of sugar is 10^23

c.)

3Pb(NO3)2 + 2AlCl3 --> 3PbCl2 + 2Al(NO3)3

theoritically from this equation we get no of moles of pbcl2 is the same as the number of moles of pb(NO3)2

if 332g of pb(NO3)2 reacts to produce 278 g of pbcl2

so 8 grams produces 6.7 grams approximately

b.) the excess reactant in this case is alcl3 as it is 0.02 moles and pb(NO3)2 is 0.024 but it should be 0.03 for perfect analysis

c.) 0.004 moles of alcl3 remains and 0.004*133 and 0.532 g

d.)the percentage yield is calculated by comparing the no of moles of pbcl2 and pb(NO3)2

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