Thanks! What mass of Al2(SO4)3 is required to make 57 mL of a 0.080-M solution o

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Thanks!

What mass of Al2(SO4)3 is required to make 57 mL of a 0.080-M solution of Al2(SO4)3? How many moles of aluminum ions are present in the solution? What is the total concentration of all ions (the sum of their individual concentrations) in aqueous solutions of the following? Hint: Each substance is an electrolyte that dissociates in water to produce ions. Use a table of polyatomic ions if you do not recognize the polyatomic ion. For example. Na2SO4 rightarrow 2Na1+ + S042- when it dissolves, so a 1 M soln of Na2S04 is 2M in Na1+ and 1M in SO42- and the total concentration of ions is 2 M + 1 M = 3M.

Explanation / Answer

1.55952 g

0.00912 mol

2)

0.176

0.168

0.102

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