Table Answer A B C D E F Solute Solute Mass Mol of Solute Volume of Solution Mol

Question

Table   Answer A B C D E F

Solute           Solute Mass           Mol of Solute               Volume of Solution                 Molarity

MgSO4             0.588g                       A                                  25.0ml                                  B

NaOH                    C                          D                                  100.0ml                              1.75M

CH3OH              12.5g                        E                                       F                                  0.500M

Explanation / Answer

A = 0.588/120.366 = 0.004885

B = Molarity = 0.004885/0.025 = 0.1954

C= NaOH mass = 1.75 x0.1 x 40 = 7 gm

D = NaOH moles = 1.75 x0.1 = 0.175

E = CH3OH moles = 12.5/32 = 0.39 moles

F = 0.39/0.5 = 0.781 liters = 781 ml

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