This is a FIVE PART QUESTION: A student burns a peanut beneath an aluminum soft-

Question

This is a FIVE PART QUESTION:

A student burns a peanut beneath an aluminum soft-drink can fillew with water. The peanut weighed 0.780g before combustion and 0.054 g after combustion. The temperature change of an aluminum can filled with 200 ml of water was 15.3 C.

1. What is the mass of the peanut burned?

2. What is the mass of water in the can?

3. Calculate the amount of endergy in Cal of the peanut:

4. Calculate the amount of energy per gram (Cal/g) of the nut:

5. Calculate the amount of energy per gram (KJ/g) of the nut:

Explanation / Answer

a) The mass of the peanut burned is just mass after minus mass before:

0.780g - 0.054g
= 0.726g of peanut were burned.

b) 200g because water is 1g/mL

c) The increase in temperature was 15.3C. Water's specific heat is 4.18J/oC. that means for every degree increase of 1mL of water, it takes 4.18J of energy:

15.3 x 4.18 x 200= 12790.8J

There are 1000J in 1 cal and 1000cal in one Cal. (Note the capital C)

12.7908 cal per peanut, or 0.013Cal per peanut.

d) 12790.8J per 0.726 grams = 17618.2J per gram, or 17.618cal per gram, or 0.018Cal per gram.

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