A buffer solution contaisn 0.120 M acetic acid and 0.150 M sodium acetate. a) ho
ID: 781955 • Letter: A
Question
A buffer solution contaisn 0.120 M acetic acid and 0.150 M sodium acetate.
a) how many moles of acestic acid and of soidum acetate are present in 50.0 mL of solution?
b) if we add 5.55 mL of 0.092 M NaOH to the solution in part a , how many moles of acetic acid, sodium acetate, and Naoh will be present after the reaction is done?
c) if we add 0.50 mL of 0.087 M HCL to teh solution in part a, how many moles of acetic acid, sodium acetate, and NaOH will be present after the reaction is done?
d) determine the PH you expect to find for the three solutions in parts a, b, and c.
PLEASE SHOW ALL WORK
Explanation / Answer
a)
0.120 M/lit, 0.150 m/lit
= 0.120 / 20
= 0.006 moles
= 0.150 / 20
= 0.0075 moles
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b)
5.55 ml of 0.092m of NaOh = 0.0005 m
hence it reduces acetic acid to 0.0055m, increases naacetate to 0.008 m
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