Balance the following redox reaction if it occurs in neutral solution. What are

Question

Balance the following redox reaction if it occurs in neutral solution. What are the coefficients in front of Ti2+(aq) and Fe2+(aq) in the balanced reaction?

Ti2+(aq) + Fe3+(aq) ----> Ti4+(aq) + Fe2+(aq)

a) 1 and 2

b) 2 and 1

c) 2 and 2

d) 3 and 1

e) 1 and 3

Please show/explain how to find the answer to this problem. I know how to balance redox reactions in acidic and basic solutions. How is it different for neutral solutions?

An answer explaining what the answer to the problem is, how it was found, and how neutral solutions differ from acidic/basic solutions- will receive FULL points. Thank you in advance!

Explanation / Answer

a) 1 and 2

we just have to balance the charge on both the sides

balancing the charge means balance of number of electrones

so the half reaction becomes

Ti2+(aq)--------->Ti4+(aq) +2 e(-1)

and

2 Fe3+(aq) +2 e(-1) -----> 2Fe2+(aq)

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