Please provide an explanation as well. The Edison storage cell is represented as

Question

Please provide an explanation as well.

The Edison storage cell is represented as follows: Fe(s) | FeO(s) | KOH(aq . C) | Ni2O3(s) | NiO(s) | Ni(s) where C indicates the concentration in mol / L of the aqueous solution of KOH. All the other cell elements are pure solids. The half-cell reactions (written as reductions) and their corresponding standard reduction potentials are : Ni2O3(s) + H2O(liq) + 2 e- 2 NiO(s) + 2 OH-(aq) E0( Ni2O3(s) / NiO(s)) = +0.4 V FeO(s) + H2O(liq) + 2 e- Fe(s) + 2 OH-(aq) E0( FeO(s) / Fe(s)) =-0.87 V What is the cell reaction? What is the standard electromotive force E0 of the cell? What is the electromotive force of the cell when the molar concentration of the KOH solution is C = 0.050 mol / L? What is the electromotive force of the cell when the molar concentration of the KOH solution is C = 2.50 mol / L?

Explanation / Answer

The half-cell reaction at the cathode:

2 NiOOH + 2 H2O + 2 e%u2212 %u2194 2 Ni(OH)2 + 2 OH%u2212

and at the anode:

Fe + 2 OH%u2212 %u2194 Fe(OH)2 + 2 e%u2212

(Discharging is read left to right, charging is from right to left.)[7]

1.65 volts.

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