Question
thanks for all the help guys!!
Relationship between free energy and the equilibrium constant The standard free energy change, Delta G degree, and the equilibrium constant K for a reaction can be related by the following equation: Delta G degree = -RT ln K where T is the Kelvin temperature and R is equal to 8.314 J/(mol middot K). Calculate the equilibrium constant for the following reaction at room temperature, 25 degree C: BaCO3(s) rightarrow BaO(s) + CO2(g) Express your answer numerically to three significant figures. plusminus Gibbs Free Energy: Equilibrium Constant Barium oxide, BaO, is manufactured by decomposition of barium carbonate, BaCO3, in a furnace: BaCO3(s) rightarrow BaO(s) + CO2(g) The heat produced by a furnace maintained at a temperature of 600 K can decompose barium carbonate to barium oxide. The spontaneity of a reaction can be determined from the free energy change for the reaction, Delta G degree A reaction is spontaneous when the free energy change is less than zero. A reaction is nonspontaneous when the free energy change is greater than zero. A reaction is in equilibrium when the free energy change is equal to zero. Relation among thermodynamic quantities The thermodynamic properties for a reaction are related by the equation that defines the standard free energy, Delta G degree, in kJ/mol: Delta G degree = DeltaH degree - TDeltaS degree where DeltaH degree is the standard enthalpy change in kJ/mol and DeltaS degree is the standard entropy change in J/(mol middot K). A good approximation of the free energy change at other temperatures, Delta GT, can also be obtained by utilizing this equation and assuming enthalpy (DeltaH degree) and entropy (DeltaS degree) change little with temperature. For the decomposition of barium carbonate, consider the following thermodynamic data: Calculate the temperature in kelvins above which this reaction is spontaneous. Express your answer to five significant figures and include the appropriate units. Radicals: Free Radical Halogenation of 2-methylpropane with Br2 and hv For the compound shown below, draw the major product of free-radical bromination. Interactive MarvinView
Explanation / Answer
Part A:
T=1415K
PartB:
K=2.148x10^-52
Part C:
(CH3)3CBr
