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A straight 2.10 m wire carries a typical household current of 1.50 A (in one dir

ID: 779204 • Letter: A

Question

A straight 2.10 m wire carries a typical household current of 1.50 A (in one direction) at a location where the earth's magnetic field is 0.550 gauss from south to north.

Find the direction of the force that our planet's magnetic field exerts on this cord if is oriented so that the current in it is running from west to east. (upward, downward, no force, east to west)

Find the magnitude of the force that our planet's magnetic field exerts on this cord if is oriented so that the current in it is running from west to east.

Find the direction of the force that our planet's magnetic field exerts on this cord if is oriented so that the current in it is running vertically upward.

Please ChooseThe force is directed from east to west. The force is directed from west to east. The force is directed from north to south. The force is directed from south to north.

Find the magnitude of the force that our planet's magnetic field exerts on this cord if is oriented so that the current in it is running vertically upward.

Find the direction of the force that our planet's magnetic field exerts on this cord if is oriented so that the current in it is running from north to south.

Please ChooseThe force is directed upward. The force is directed downward. There is no force exerting on the wire. The force is directed from north to south.

Find the magnitude of the force that our planet's magnetic field exerts on this cord if is oriented so that the current in it is running from north to south.

Is the magnetic force ever large enough to cause significant effects under normal household conditions?

Please ChooseYes No

Explanation / Answer

a) when current flows from west to East

direction of F : Upward

b) magnitude of force, F = B*I*L*sin(90)

= 0.55*10^-4*1.5*2.1*1

= 1.73*10^-4 N

c) when current flows vertically upward

direction of F: West

d) magnitude of force, F = B*I*L*sin(90)

= 0.55*10^-4*1.5*2.1*1

= 1.73*10^-4 N

e) when current flows from North to souht

direction of F : no force

f) magnitude of force, F = B*I*L*sin(180)

= 0

h) No.

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