South Carolina State ur X A Adabe Flash Player issues + phpid-4908274 Jump to...

Question

South Carolina State ur X A Adabe Flash Player issues + phpid-4908274 Jump to... 3/5/2018 1199 PM0/100 Print Calutor Periodic Table Question 1 of 10 Sapling Learning A partidle that carries a net charge of-41.8 JC is held in a region of constant, uniform electric field. The electric field vector is oriented 55.2 dockwise from the vertical axis, as how much work is done by the electric field as the particle is made to move a distance of d-0.556 m straight up? What is the potential diflerence between the particle's inital and final positions (V-V?

Explanation / Answer

(a) Here, find the pojection of the force onto the vertical axis then just do Work = Force*distance.

Now, projection of the electric field on to the vertical axis:
Ey = E*cos(theta) = 9.32 N/C * cos(55.2) = 5.32 N/C

so -  

Fy = q*Ey = -41.8 *10^-6 C * 5.32 N/C = -222.38 * 10-6 N


Work = Fy*sy = -222.38 * 10^-6 N * 0.556 m = -123.6 x 10^-6 J = -1.24 x 10^-4 J

(b) Now use the expression -

V = U / q = W / q

Put the values -

V = (-1.24 x 10^-4) / (-41.8 x 10^-6) = 3.0 V

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.