2. A doubly charged helium atom whose mass is 6.6 10 -27 kg is accelerated by a

Question

2. A doubly charged helium atom whose mass is 6.6 10-27 kg is accelerated by a voltage of 2500 V.

(a) What will be its radius of curvature if it moves in a plane perpendicular to a uniform 0.302 T field?
_______________m
(b) What is its period of revolution?
_________________ s

3. A rectangular loop of wire lies in the same plane as a straight wire, as shown in the figure below. There is a current of 2.5 A in both wires.

Determine the magnitude and direction of the net force on the loop.
Magnitude
____________N
Direction

_______________

4. A straight stream of protons passes a given point in space at a rate of 1010 protons/s. What magnetic field do they produce 1.5 m from the beam?
__________________ T

Explanation / Answer

(2) From the conservation of energy and assuming negligible relativistic effects -

E_kin = E_el

=> (1/2)·m·v² = q·U
=> v = (2·q·E/m)
= (2 · 2·1.6022×10-19C · 2500V / 6.6×10-27kg)
= 4.927×10+5 m/s

Again, for the stationary motion Lorentz force equals centripetal force on the moving atom
m·²·r = q·v·B
=> m·v²/r = q·v·B
=> r = m·v / (q·B)
= 6.6×10-27kg · 4.927×10+5m/s / (2·1.6022×10-19C · 0.302 T)
= 0.0336 m

(b) Use the expression -

T = 2·/
= 2··r/v
= 2 · · 0.0336 m / 4.927×10+5m/s
= 4.28×10-7 s

Related Questions

Navigate

• Browse (All)
• Browse 2
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.