information. /23/2018 11:59 PM 10/100 Gra Print Calculator I\'d Periodic Table t

Question

information. /23/2018 11:59 PM 10/100 Gra Print Calculator I'd Periodic Table tion 3 of 10 Ma Sapling Learning An initially uncharged air-filled capacitor is connected to a 2.75-V charging source. As a result, 4.95 x10 C of charge is transfered from one of the capacitor's plates to the other. Then, while the capacitor remains connected to the plates, completely filling the space. The source, a sheet of dielectric material is inserted between its constant of this substance is 3.13. Find the capacitors difference and charge after the insertion. Potential difference after insertion of dielectric Number Charge after insertion of dielectric: Number OPrvous Check Answer Next lint about us careers privacy policy terms of use contact us help

Explanation / Answer

V = potential difference = 2.75 volts

Qo = charge stored by the capacitor when without dielectric = 4.95 x 10-5 C

Co = Capacitance of capacitor without the dielectric

Using the formula

Qo = Co V

(4.95 x 10-5 ) = Co (2.75)

Co = 1.8 x 10-5 F

k = dielectric constant = 3.13

C = Capacitance with the dielectric = k Co = 3.13 (1.8 x 10-5 ) = 5.634 x 10-5 F

Potential difference is due to the external charging source so it remains same

V = potential difference after insertion = 2.75 volts

New charge stored , Q = C V = (5.634 x 10-5 )(2.75) = 0.000155 C

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