The wire above carries a current I that is decreasing with time at a constant ra
ID: 778943 • Letter: T
Question
The wire above carries a current I that is decreasing with time at a constant rate. The induced emf in each of the loops is such that A) no emf is induced in any loop B) all loops experience 1. counterclockwise emf C) loop A has clockwise emf, loop B D) loop A has counterclockwise emf, E) loop A has counterclockwise emf, has no induced emf, and loop C has counterclockwise emf loop B has no induced emf, and loop C has clockwise emf loop B clockwise emf, and loop C has clockwise emf flip 6. A square coil of wire with 15 turns and an area of 0.4 m2 is placed parallel to a magnetic field of 0.75 T. The coil is flipped so its plane is perpendicular to the magnetic field in 0.050s. What is the magnitude of the induced emf? Hint: this means the field cutting through the coil goes from 0 to 0.75T in .050s. (A) 6.0 V (B) 36 V (C) 45 V (D) 90 VExplanation / Answer
ans)
1.
answer is D
according to lenz law
because in A the magnetic field is decreasing,so emf will set up to counter it,so in A emf will be set up to increase the net field .so it will be in ANTICLOCKWISE
similarly in B, THE MAGNETIC FIELD IS INTO THE PAPER AND DECRESING,SO EMF WILL TRY TO INCRESE IT.SO CURRENT WILL BE IN CLOCKWISE
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